这篇文章介绍了Queryable.Union 方法实现json格式的字符串合并的具体实例,有需要的朋友可以参考一下
1.在数据库中以json字符串格式保存,如:[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}]
2.添加新内容后合并不相同的数据。如果name相同,以最新的数据替换原来的数据。
如:数据库中原保存的数据是[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}]
新加的数据为[{"name":"张三","time":"12","area":"27.70533","conc":"4.12136"},{"name":"王五","time":"4","area":"77","conc":"8.788"}]
则替换后的数据为[{"name":"张三","time":"12","area":"27.70533","conc":"4.12136"},{"name":"王五","time":"4","area":"77","conc":"8.788"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}]
代码如下:
复制代码 代码如下: public void InsertOrUpdateOnlyItem(List<tblLims_Ana_LE_Import_Common> listLe) { var listLeInsert = new List<tblLims_Ana_LE_Import_Common>(); var listLeUpdate = new List<tblLims_Ana_LE_Import_Common>(); foreach (var le in listLe) { tblLims_Ana_LE_Import_Common model = le; var own = CurrentRepository.Find(a => a.fldTaskID == model.fldTaskID && a.fldBizCatID == model.fldBizCatID && a.fldItemCode == model.fldItemCode && a.fldNumber == model.fldNumber && a.fldSampleCode == model.fldSampleCode); if (own != null) { var ser = new JavaScriptSerializer();
var listown = ser.Deserialize<List<Dictionary<string, string>>>(own.fldImportData); //原数据 var listmodel = ser.Deserialize<List<Dictionary<string, string>>>(model.fldImportData); //新数据 IEqualityComparer<Dictionary<string, string>> ec = new EntityComparer(); //自定义的比较类 own.fldImportData = ser.Serialize(listmodel.Union(listown, ec)); //合并数据
listLeUpdate.Add(own); } else { listLeInsert.Add(model); } } CurrentRepository.UpdateAll(listLeUpdate); CurrentRepository.InsertAll(listLeInsert); CurrentRepository.Save(); }
tblLims_Ana_LE_Import_Common 为数据库中存数据的表
Union() 方法中用到的自定义比较类:
复制代码 代码如下: /// <summary> /// 自定义比较类 /// </summary> public class EntityComparer : IEqualityComparer<Dictionary<string, string>> { public bool Equals(Dictionary<string, string> x, Dictionary<string, string> y) { if (ReferenceEquals(x, y)) return true;
if (ReferenceEquals(x, null) || ReferenceEquals(y, null)) return false;
return x["name"] == y["name"]; //如果名称相同就不追加 }
public int GetHashCode(Dictionary<string, string> obj) { if (ReferenceEquals(obj, null)) return 0; int hashName = obj["name"] == null ? 0 : obj["name"].GetHashCode(); int hashCode = obj["name"] == null ? 0 : obj["name"].GetHashCode(); return hashName ^ hashCode; } }
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