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本文给大家分享php ajax无刷新上传图片与图片下载功能的实现代码，非常不错，具有参考借鉴价值，需要的的朋友参考下
php ajax无刷新上传图片与图片下载功能的实现代码如下所示：
<meta charset="utf-8" >
<form id= "uploadForm">
<p >指定文件名： <input type="text" name="filename" value= ""/></p >
<p>
上传文件：
<input type="file" name="photo" onchange="showPreview(this)" class="file" />
<img id="portrait" src="" width="70" height="75">
</p>
<input type="button" value="上传" onclick="doUpload()" />
</form>
<script src="http://www.haoyunyun.cn/jquery.js"></script>
<script>
function doUpload() {
var formData = new FormData($( "#uploadForm" )[0]);
$.ajax({
url: 'submit.php' ,
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
alert(returndata);
},
error: function (returndata) {
alert(returndata);
}
});
}
</script>
<script type="text/javascript">
function showPreview(source) {
var file = source.files[0];
if (window.FileReader) {
var fr = new FileReader();
fr.onloadend = function(e) {
document.getElementById("portrait").src = e.target.result;
};
fr.readAsDataURL(file);
}
}
</script>
submit.php
<?php
if($_FILES['photo']['error']>0){
echo "上传文件失败";
die;
}
$dir='./photo/';
$type=substr($_FILES['photo']['name'],strrpos($_FILES['photo']['name'],'.'));
$filename=time().rand(1000,9999).$type;
if(is_uploaded_file($_FILES['photo']['tmp_name'])){
move_uploaded_file($_FILES['photo']['tmp_name'],$dir.$filename);
echo "上传成功";
}else{
echo "上传文件失败";
}
遍历数据库数据
<?php
header("content-type:text/html;charset=utf-8");
$link=mysql_connect("127.0.0.1",'root','root');
mysql_select_db("php9",$link);
mysql_query("set names utf8");
//查询数据中的总条数
$sql="select count(id) as count from upload";
$arr=mysql_query($sql);
$result=mysql_fetch_assoc($arr);
//获得总条数
$size=$result['count'];
//每页显示2条数据
$length=6;
//计算出多少页
$pages=ceil($size/$length);
$page=isset($_GET['page'])?$_GET['page']:1;
if($page<=0){
$page=1;
}
if($page>$pages){
$page=$pages;
}
//数据从第几条开始
$start=($page-1)*$length;
$sql="select * from upload limit $start,$length";
$res=mysql_query($sql);
?>
<center>
<table border="1">
<div>
<?php
while($a=mysql_fetch_assoc($res)){
?>
<ul>
<li><?php echo $a['id'] ?></li>
<li><?php echo $a['username'] ?></li>
<li><a href="photo.php" rel="external nofollow" ><img src="<?php echo $a['dir'] ?>" width="80px" ></a> </li>
<li><?php echo $a['desc1'] ?></li>
<li>
<a href="photo3.php?dir=<?php echo $a['dir'] ?>" rel="external nofollow" >下载</a>
<a href="photo4.php?id=<?php echo $a['id'] ?> && dir=<?php echo $a['dir'] ?>" rel="external nofollow" >删除</a>
</li>
</ul>
<?php
}
?>
</div>
</table>
<a href="photo2.php?page=1" rel="external nofollow" >首页</a>
<a href="photo2.php?page=<?php echo $page-1 ?>" rel="external nofollow" >上一页</a>
<a href="photo2.php?page=<?php echo $page+1 ?>" rel="external nofollow" >下一页</a>
<a href="photo2.php?page=<?php echo $pages ?>" rel="external nofollow" >尾页</a>
</center>
<style>
*{
margin: 0;
padding: 0;
}
div{
width:900px;
height: 850px;
border: 1px solid #28a4c9;
margin: auto;
}
img{
width: 200px;
height: 130px;
margin-left: 100px;
}
ul{
width: 400px;
height: 300px;
float: left;
}
li{
list-style: none;
margin-left: 10px;
}
</style>
下载代码
<?php
header("content-type:text/html;charset=utf-8");
$dir=$_GET['dir'];
$filename=substr($dir,strrpos($dir,'/')+1);
header("Content-type:image");
header("content-disposition:attachment;filename=$filename");
readfile($dir);
?>
以上所述是小编给大家介绍的PHP中ajax无刷新上传图片与图片下载功能，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对脚本之家网站的支持！ | 
发表于 2017-2-21 17:13:09
