如何把图片上传到数据库中并显示出来？upload.htm ' 上传页面. <html> <body> <p align="center">千花飞舞之图片上传</p>
<center>
<form name="mainForm" enctype="multipart/form-data" ' 这个Form属性是得到上传的数据的关键.
action="process.asp" method=post>
<input type=file name=mefile><br>
<input type=submit name=ok value="上传">
</form>
</center>
</body></html>
process.asp ' 处理浏览器中送来的数据. <%
response.buffer=true
formsize=request.totalbytes
formdata=request.binaryread(formsize)
bncrlf=chrB(13) & chrB(10)
divider=leftB(formdata,clng(instrb(formdata,bncrlf))-1)
datastart=instrb(formdata,bncrlf & bncrlf)+4
dataend=instrb(datastart+1,formdata,divider)-datastart
mydata=midb(formdata,datastart,dataend)
set connGraph=server.CreateObject("ADODB.connection")
connGraph.ConnectionString="driver={Microsoft Access Driver (*.mdb)}; DBQ=" & server.MapPath("images.mdb") & ";uid=;PWD=;"
connGraph.Open
set rec=server.createobject("ADODB.recordset")
rec.Open "select * from [images] where id is null",connGraph,1,3
rec.addnew
rec("img").appendchunk mydata
rec.update
rec.close
set rec=nothing
set connGraph=nothing
%>
showimg.asp ' 显示图片.
<%
set connGraph=server.CreateObject("ADODB.connection")
connGraph.ConnectionString="driver={Microsoft Access Driver (*.mdb)}; DBQ=" & server.MapPath("images.mdb") & ";uid=;PWD=;"
connGraph.Open
set rec=server.createobject("ADODB.recordset")
strsql="select img from images where id=" & trim(request("id"))
rec.open strsql,connGraph,1,1
Response.ContentType = "image/*" ' 在输出到浏览器之前一定要指定Response.ContentType = "image/*",以便正常显示图片.
Response.BinaryWrite rec("img").getChunk(7500000)
rec.close
set rec=nothing
set connGraph=nothing
%> [1] | 
匿名
发表于 2023-8-24 17:38:36
