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第一个办法，这个程序可以进行万亿以下的货币金额转换（够用的了吧），其中汉字与数字均按一位计： Function AtoC(a As Currency) As String
' 定义两个字符串，A的值最多是两位小数.
Dim String1 As String ' 如下定义.
Dim String2 As String ' 如下定义.
Dim String3 As String ' 从原A值中取出的值.
Dim I As Integer ' 循环变量. Dim J As Integer ' A的值乘以100的字符串长度.
Dim Ch1 As String ' 数字的汉语读法.
Dim Ch2 As String ' 数字位的汉字读法.
Dim nZero As Integer ' 用来计算连续的非零数是几个.
String1 = "零壹贰叁肆伍陆柒捌玖"
String2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"
'MsgBox CStr(a * 100)
If InStr(1, CStr(a * 100), ".") <> 0 Then
err.Raise 5000, , "该函数( AtoC() )只转换两位小数以内的数值!"
End If
J = Len(CStr(a * 100))
String2 = Right(String2, J) ' 取出对应位数的StrING2的值.
For I = 1 To J
String3 = Mid(a * 100, I, 1) ' 取出需转换的某一位的值.
If String3 <> "0" Then
Ch1 = Mid(String1, Val(String3) + 1, 1)
Ch2 = Mid(String2, I, 1)
nZero = nZero + 1 ' 表示本位不为零.
Else
If nZero <> 0 Or I = J - 9 Or I = J - 5 Or I = J - 1 Then
If Right(AtoC, 1) = "零" Then AtoC = Left(AtoC, Len(AtoC) - 1)
Ch1 = "零"
Else
Ch1 = ""
End If
If I = J - 10 Then ' 如果转换的数值需要扩大，则要改动以下表达式 I 的值.
Ch2 = "亿"
ElseIf I = J - 6 Then
If nZero <> 0 Then
Ch2 = "万"
' nZero = 0
End If
ElseIf I = J - 2 Then
Ch2 = "元"
ElseIf I = J Then
Ch2 = "整"
Else
Ch2 = ""
End If
nZero = 0
End If
AtoC = AtoC & Ch1 & Ch2
Next I
AtoC = Replace(AtoC, "零元", "元")
AtoC = Replace(AtoC, "零万", "万")
AtoC = Replace(AtoC, "零亿", "亿")
AtoC = Replace(AtoC, "零整", "整")
' 以上将多余的零去掉
End Function 第二个办法：照下面写就成了！ <%
dim str(9)
str(0)="零"
str(1)="壹"
str(2)="贰"
str(3)="叁"
str(4)="肆"
str(5)="伍"
str(6)="陆"
str(7)="柒"
str(8)="捌"
str(9)="玖"
aa=Request.form("source")
hh=formatnumber(aa,2,-1)
aa=replace(hh,".","")
aa=replace(aa,",","")
for i=1 to len(aa)
s=mid(aa,i,1)
mynum=str(s)
select case(len(aa)+1-i)
case 1: k= mynum&"分"
case 2: k= mynum&"角"
case 3: k= mynum&"元"
case 4: k= mynum&"拾"
case 5: k= mynum&"佰"
case 6: k= mynum&"仟"
case 7: k= mynum&"万"
case 8: k= mynum&"拾"
case 9: k= mynum&"佰"
case 10: k= mynum&"仟"
end select
m=m&k
next
%>
<html>
<head>
<title>精彩春风之数字大小写转换</title>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
</head>
<!--
Elseif(s=".") then
n=m
i=i+2
for j=i to len(aa)
s=mid(aa,i,1)
mynum=str(s)
select case(len(aa)+1-i)
case 1: p= mynum&"分"
case 2: p= mynum&"角"
end select
m=m&p
next
-->
<body>
<form method="post" name="forma">
<input type="text" name="source" value="<%=hh%>">
=
<input type="text" name="result" value="<%=m%>" size="40">
<input type="submit" name="Submit" value="开始转换" >
</form>
</body></html> | 
发表于 2006-11-16 00:00:00
