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upload.asp
<form action=http://<％= Request. ServerVariables(SERVER_NAME)>/wdread.asp method=post>
<p>主题: <input type=text name=subject><br>
作者:<input name=author type=text><br>
发布时间: <input name=date1 type=text><br>
上载文件:<input type=file name=filename>
发往URL: <input type=hidden name=TargetURL value=http://<％= Request.ServerVariables(SERVER_NAME)％>/users/<％=Request.ServerVariables(LOGON_USER) ％> size=20><br>
<input type=submit value=确定> </p>
</form>
wdread.asp
<form enctype=multipart/form－data action=http://<％= Request.ServerVariables (SERVER_NAME) ％>/scripts/cpshost.dll?PUBLISH?wdwriter.asp method=post name=form1>
上载文件:<input type=file name=filename value=<％=session(filename)％>>
<input type=hidden name=TargetURL value=http://<％= Request.ServerVariables (SERVER_NAME) ％>/users/wdls > <input type=button name=upload value=确定>
</form>
<scripts language=VBScript>
' 在上载时应对表单域filename的值与upload.asp程序中的域值进行比较, 因为在upload.asp中输入的文件名在本程序中预置给表单域filename,一旦客户端重新输入新的文件名后提交确认,会使程序wdwriter.asp中写入数据库的文件名与实际上载的文件名不一样, 导致网页连接出错.此处进行判断,如果两者相等,则立即上载,否则取消操作.
<!－－ sub upload_onclick() set myform=window.document.form1 tmp=myform.filename.value if strcomp(tmp,<％=session (filename)％>)=0 then form1.submit else
msgbox 噢,您输入的文件名有误,请重新输入！ end if
end sub
－－>
</scripts>
wdwriter.asp
<％ Set mydata = Server.CreateObject (ADODB.Connection) mydata.Open DSN=xczh;UID=sa;PWD=; ' 打开数据库.
date1=session(date1) ' 取各表单域的值.取时间.
subject=session(subject) ' 取文件主题.
author=session(subject) ' 取作者.
filename=session(filename) ' 取文件名.
TargetURL= session(TargetURL) ' 取文件在服务器中存放的物理地址.
sqlstr=insert into wdlsb values( ＆ sn ＆ ,＆ subject ＆ ', ＆ date1 ＆ ',＆filename ＆ ', ＆ TargetURL ＆', ＆ author ＆ ') ' 写数据库并保存.
Mydata.Execute(sqlstr)
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发表于 2006-11-16 00:00:00
